Practice portal › Rotational Motion › Rolling Motion
Asked in JEE Main 17th March 1st Shift 2021 · Rolling on an incline
All four start from rest and cover the same distance, so the one with the largest acceleration arrives first.
a=(g sin θ)/(1+k) with k=I/(mR²), so the largest acceleration goes with the smallest k.
Ring: k=1. Disc: k=1/2. Solid cylinder: k=1/2. Solid sphere: k=2/5.
The smallest is 2/5, the solid sphere.
The answer is 4.
Note that (2) and (3) are the same body as far as this calculation goes — a disc and a solid cylinder both have k=1/2 — so they would arrive together, in second place.
Mass and radius are the same for all four, but they would have cancelled anyway: only shape decides the order.
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