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A string is wrapped around the rim of a wheel of moment of inertia 0.40 kg m² and radius 10 cm. The wheel is free to rotate about its axis. Initially the wheel is at rest. The string is now pulled by a force of 40 N. The angular velocity of the wheel after 10 s is x rad/s, where x is ______.

Asked in JEE Main 9th April 1st Shift 2024 · Pulleys, strings and hanging masses

Answer: 100

Step-by-step solution

The string pulls tangentially at the rim, so τ=FR=(40)(0.1)=4 N m.

α=τ/I=4/(0.40)=10 rad s⁻².

The force is steady, so α is constant and, starting from rest, ω=α t.

ω=(10)(10)=100 rad s⁻¹.

x=100.

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