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Asked in JEE Main 2011 · Pulleys, strings and hanging masses
Body: mg-T=ma.
Pulley (a disc of the same mass m): TR=1/2mR²α, and with a=α R this gives T=1/2ma.
Substitute: mg-1/2ma=ma.
mg=3/2ma, so a=(2g)/3.
Note that R cancels completely — only the shape of the pulley matters, not its size.
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