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The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the centre will be ______ m. (The length of the rod is 10√3 m.)

Asked in JEE Main 26th July 2nd Shift 2022 · Radius of gyration and numericals

Answer: 5

Step-by-step solution

For a thin rod about a perpendicular axis through its centre, I=(ML²)/(12).

Radius of gyration: k²=I/M=(L²)/(12).

k²=((10√3)²)/(12)=(300)/(12)=25.

k=5 m.

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