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A solid sphere A of radius 5 cm is rotating about an axis PQ which lies a distance 10 cm from the centre of the sphere. Its radius of gyration about PQ will be √x cm. The value of x is ______.

Asked in JEE Main 24th Jan 1st Shift 2023 · Radius of gyration and numericals

Answer: 110

Step-by-step solution

Work in centimetres throughout, since the answer is asked for in cm.

Sphere about its own diameter: I_cm=2/5MR²=2/5M(25)=10M.

Parallel-axis theorem, with d=10 cm: I=10M+M(100)=110M.

Radius of gyration: k=√I/M=√110 cm.

x=110.

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