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Asked in JEE Main 2008 · Standard bodies and axis theorems
About the perpendicular axis through the centre: I_cm=m/(12)(a²+a²)=(ma²)/6.
The corner is half a diagonal from the centre: d=(a√2)/2=a/(√2), so d²=(a²)/2.
Parallel-axis theorem: I=(ma²)/6+m(a²)/2=(ma²)/6+(3ma²)/6=(4ma²)/6.
I=2/3ma².
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