A force of -P̂k acts on the origin of the coordinate system. The torque about the point (2, -3) is P(âi+b̂j). The ratio a/b is x/2. Find the value of x.

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3. The vector ⃗r runs from the reference point to where the force acts. Force applied at O=(0,0,0); reference point (2,-3,0). ⃗r=(0,0,0)-(2,-3,0)=(-2, 3, 0) and ⃗F=(0, 0, -P). ̂i component: (3)(-P)-(0)(0)=-3P. ̂j component: -[(-2)(-P)-(0)(0)]=-2P. ̂k component: (-2)(0)-(3)(0)=0. τ⃗=P(-3̂i-2̂j), so a=-3 and b=-2. a/b=(-3)/(-2)=3/2, and this is given as x/2. x=3.

A force of -P̂k acts on the origin of the coordinate system. The torque about the point (2, -3) is P(âi+b̂j). The ratio a/b is x/2. Find the value of x.

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