Practice portal › Rotational Motion › Moment of Force and Torque
Asked in JEE Main 25th June 1st Shift 2022 · Torque and moment of a force
τ⃗=⃗r×⃗F with ⃗r=(2,1,2) and ⃗F=(3,4,-2).
̂i component: (1)(-2)-(2)(4)=-2-8=-10.
̂j component: -[(2)(-2)-(2)(3)]=-[-4-6]=10.
̂k component: (2)(4)-(1)(3)=8-3=5.
τ⃗=-10̂i+10̂j+5̂k.
Check: τ⃗·⃗r=-20+10+10=0 and τ⃗·⃗F=-30+40-10=0.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer