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Asked in JEE Main 10th Jan 1st Shift 2019 · Rolling dynamics and slipping
Newton: F-f=Ma; torque about the axis: fR=Iα=1/2 MR²/aR, so f=1/2 Ma.
F=3/2 Ma⇒ a=(2F)/(3M), and α=/aR=(2F)/(3MR).
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