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A solid sphere rolls without slipping on a horizontal plane. The ratio of the translational (centre-of-mass) kinetic energy to the rotational kinetic energy of the sphere is

Asked in JEE Main 24th Jan 2nd Shift 2025 · Rolling kinematics and energy

Answer: (4) 5/2

Step-by-step solution

KEₜᵣₐₙₛ=1/2 Mv² and KEᵣₒₜ=1/2 Iω²=1/2·2/5 MR²·(v²)/(R²)=1/5 Mv².

Ratio =(1/2)/(1/5)=5/2.

Why the other options are wrong

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