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Asked in JEE Main 27th July 2nd Shift 2022 · Rotational energy and released bodies
Unwinding cylinder: a=g/(1+I/(mR²))=g/(1+1/2)=(2g)/3=(20)/3 m/s².
v²=2a d⇒ 16=2·(20)/3d⇒ d=1.2 m=120 cm.
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