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A solid cylinder is suspended symmetrically through two massless strings wound on it (a yo-yo). The distance it should descend to unwind the strings and reach a speed of 4 m/s is ______ cm. (take g=10 m/s²)

Asked in JEE Main 27th July 2nd Shift 2022 · Rotational energy and released bodies

Answer: 120

Step-by-step solution

Unwinding cylinder: a=g/(1+I/(mR²))=g/(1+1/2)=(2g)/3=(20)/3 m/s².

v²=2a d⇒ 16=2·(20)/3d⇒ d=1.2 m=120 cm.

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