Two masses 400 g and 350 g are suspended from the ends of a light string over a heavy pulley of radius 2 cm. Released from rest, the heavier mass falls 81 cm in 9 s. The rotational inertia of the pulley is (take g=9.8 m/s²)

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(2) 9.5×10⁻³ kg m². a=(2s)/(t²)=(2(0.81))/(81)=0.02 m/s². T₁=m₁(g-a)=0.4(9.78)=3.912, T₂=m₂(g+a)=0.35(9.82)=3.437. I=((T₁-T₂)R²)/a=(0.475(0.02)²)/(0.02)=9.5×10⁻³ kg m².

Two masses 400 g and 350 g are suspended from the ends of a light string over a heavy pulley of radius 2 cm. Released from rest, the heavier mass falls 81 cm in 9 s. The rotational inertia of the pulley is (take g=9.8 m/s²)

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