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Asked in JEE Main 5th April 1st Shift 2024 · Radius of gyration and numericals
Hollow sphere about a diameter: k₁²=2/3 R².
Cylinder about AB: I₂=(M(2R)²)/(12)+(MR²)/4+M(2R)²=(67)/(12)MR², so k₂²=(67)/(12)R².
(k₁²)/(k₂²)=(2/3)/(67/12)=8/(67), so x=67.
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