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The mass per unit area of a circular disc of radius a is σ(r)=A+Br. Its moment of inertia about an axis perpendicular to the plane and through its centre is

Asked in JEE Main 8th April 1st Shift 2019 · Composite and cavity bodies

Answer: (3) 2π a⁴(A/4+(aB)/5)

Step-by-step solution

I=∫₀^a r²(A+Br) 2π r dr=2π∫₀^a (Ar³+Br⁴) dr=2π((Aa⁴)/4+(Ba⁵)/5).

Factor a⁴: I=2π a⁴(A/4+(aB)/5).

Why the other options are wrong

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