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Asked in JEE Main 27th June 1st Shift 2022 · Discrete systems and motion of the centre of mass
For the centre of mass to stay fixed, m₁Δ x₁+m₂Δ x₂=0.
10(+6)+30 Δ x₂=0⇒ Δ x₂=-2 cm.
The negative sign means the 30 kg block moves 2 cm in the direction of the 10 kg block (towards it).
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