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Asked in JEE Main 2006 · Wire, tunnel and contact-loss systems
The platform can only push the coin upward, so it must supply the downward acceleration ω²y needed at displacement y using gravity alone plus contact.
The demand is greatest at the top, where the required downward acceleration is ω²A.
Contact is first lost when ω²A=g, i.e. at an amplitude of g/(ω²).
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