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Asked in JEE Main 2018 · Wire, tunnel and contact-loss systems
Mass of one atom: m=(108×10⁻³)/(6.02×10²³)=1.794×10⁻²⁵ kg.
k=mω²=m(2π f)²=1.794×10⁻²⁵×(2π×10¹²)².
(2π×10¹²)²=3.95×10²⁵, so k=7.1 N m⁻¹.
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