A light hollow cube of side 10 cm and mass 10 g floats in water. It is pushed down and released, and executes simple harmonic oscillations of time period yπ×10⁻² s. The value of y is (take g=10 m s⁻² and the density of water as 10³ kg m⁻³)

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(4) 2. The cross-sectional area is A=(0.1)²=10⁻² m², so k=ρ Ag=10³×10⁻²×10=100 N m⁻¹. T=2π√M/k=2π√(0.01)/(100)=2π×10⁻² s. Comparing with yπ×10⁻² gives y=2.

A light hollow cube of side 10 cm and mass 10 g floats in water. It is pushed down and released, and executes simple harmonic oscillations of time period yπ×10⁻² s. The value of y is (take g=10 m s⁻² and the density of water as 10³ kg m⁻³)

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