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A simple pendulum oscillating in air has period T. Its bob is then completely immersed in a non-viscous liquid whose density is 1/(16) of the density of the material of the bob, and it stays immersed throughout. Its period of oscillation in the liquid is

Asked in JEE Main 9th April 1st Shift 2019 · Pendulum in a liquid

Answer: (2) 4T√1/(15)

Step-by-step solution

Buoyancy gives g_eff=g(1-σ/ρ)=g(1-1/(16))=(15g)/(16).

T'=T√g/(g_eff)=T√(16)/(15)=4T√1/(15).

Why the other options are wrong

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