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A simple pendulum with a string 30 cm long performs 20 oscillations in 10 s. The length of string required for the pendulum to perform 40 oscillations in the same time is ______ cm. (The mass of the bob is unchanged.)

Asked in JEE Main 23rd Jan 1st Shift 2026 · Time period, length and g

Answer: (4) 7.5

Step-by-step solution

Doubling the number of oscillations in the same time halves the period.

T∝√L, so halving T divides L by 4: L'=(30)/4=7.5 cm.

Why the other options are wrong

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