Practice portal › Oscillations › Oscillations due to a Spring
Asked in JEE Main 2011 · Mass added or removed
Momentum is conserved at the mean position: Mv=(M+m)v', with v=A₁√k/M.
Then A₂=(v')/(ω')=A₁√M/(M+m), so (A₁)/(A₂)=((M+m)/M)^1/2.
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