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A mass M attached to a horizontal spring executes SHM with amplitude A₁. When M passes through its mean position a smaller mass m is placed on it, and the two then move together with amplitude A₂. The ratio (A₁)/(A₂) is

Asked in JEE Main 2011 · Mass added or removed

Answer: (4) ((M+m)/M)^1/2

Step-by-step solution

Momentum is conserved at the mean position: Mv=(M+m)v', with v=A₁√k/M.

Then A₂=(v')/(ω')=A₁√M/(M+m), so (A₁)/(A₂)=((M+m)/M)^1/2.

Why the other options are wrong

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