Practice portal › Oscillations › Energy in SHM
Asked in JEE Main 27th July 2nd Shift 2021 · Kinetic, potential and total energy
ω=(2π)/T=(2π)/(0.2)=10π rad s⁻¹, and starting from the mean position the particle is at x=A after a quarter period.
U=1/2 mω²A²=1/2×0.5×(10π)²×(0.05)²=0.62 J.
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