Practice portal › Oscillations › Velocity and Acceleration in SHM
Asked in JEE Main 26th Feb 2nd Shift 2021 · Time, distance and displacement
One complete oscillation covers a path 4A, so 5/8 of an oscillation is a path of 5/8×4A=2.5A.
From the mean position the particle covers 2A in T/2 (mean to extreme and back to mean, then on); the remaining 0.5A is from the mean position out to A/2, which takes T/(12).
Total time =T/2+T/(12)=(7T)/(12), so α=7.
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