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A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then its periodic time in seconds is

Asked in JEE Main 10th Jan 1st Shift 2019 · v-x and a-x relations

Answer: (1) (8π)/3

Step-by-step solution

In SI units v=ω√A²-x²=ω√0.05²-0.04²=0.03ω and |a|=ω²x=0.04ω².

Setting them equal: 0.03ω=0.04ω², so ω=0.75 rad s⁻¹.

T=(2π)/(0.75)=(8π)/3 s.

Why the other options are wrong

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