Practice portal › Nuclei › Nuclear Reactions, Fission and Fusion
Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is (given binding energy per nucleon for deuteron =1.1 MeV and for helium =7.0 MeV)
Asked in JEE Main Online 2017 · Energy released in fission and fusion
- (1) 25.8 MeV
- (2) 32.4 MeV
- (3) 30.2 MeV
- (4) 23.6 MeV
Answer: (4) 23.6 MeV
Step-by-step solution
Why the other options are wrong
- (1) Subtracts only one deuteron.
- (2) Adds instead of subtracting.
- (3) Adds one deuteron binding energy instead of subtracting both.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer