The energy released in the fusion of 2 kg of hydrogen deep in the sun is E_H and the energy released in the fission of 2 kg of ²³⁵U is E_U. The ratio (E_H)/(E_U) is approximately (Consider the fusion reaction as 4 ¹₁H+2e⁻→⁴₂He+2 u+6γ+26.7 MeV, energy released in the fission reaction of ²³⁵U is 200…

Question

The energy released in the fusion of 2 kg of hydrogen deep in the sun is E_H and the energy released in the fission of 2 kg of ²³⁵U is E_U. The ratio (E_H)/(E_U) is approximately (Consider the fusion reaction as 4 ¹₁H+2e⁻→⁴₂He+2
u+6γ+26.7 MeV, energy released in the fission reaction of ²³⁵U is 200 MeV per fission nucleus and N_A=6.023×10²³)

Accepted Answer

(3) 7.62. E_H=(2000×6.023×10²³)/4×26.7=8.04×10²⁷ MeV E_U=(2000)/(235)×6.023×10²³×200=1.03×10²⁷ MeV (E_H)/(E_U)≈7.8, closest to 7.62

Step-by-step solution

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