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Asked in JEE Main 5th April 1st Shift 2024 · Breaking stress and maximum load
Idea: a hanging wire is most stressed at the top, where the whole of its own weight acts on the cross-section.
For a wire of area A and length L, the weight is ρ ALgₚ, so the stress at the support is (ρ ALgₚ)/A=ρ Lgₚ; the area cancels and only the length matters.
Here gₚ=g/3=(10)/3 m s⁻² and ρ=6×10⁴ kg m⁻³, so ρ gₚ=6×10⁴×(10)/3=2×10⁵ N m⁻³.
Setting ρ gₚL=1.2×10⁸ gives L=(1.2×10⁸)/(2×10⁵).
L=600 m.
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