The increase in pressure required to decrease the volume of a water sample by 0.2% is P×10⁵ N m⁻². Bulk modulus of water is 2.15×10⁹ N m⁻². The value of P is .

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43. Given: (Δ V)/V=0.2%=2×10⁻³ and B=2.15×10⁹ N m⁻². B=(Δ p)/(Δ V/V), so Δ p=B(Δ V)/V. Δ p=2.15×10⁹×2×10⁻³=4.3×10⁶ N m⁻². Written as P×10⁵, this is 43×10⁵ N m⁻². Hence P=43.

The increase in pressure required to decrease the volume of a water sample by 0.2% is P×10⁵ N m⁻². Bulk modulus of water is 2.15×10⁹ N m⁻². The value of P is ______.

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