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An object is located at 2 km beneath the surface of the water. If the fractional compression (Δ V)/V is 1.36%, the ratio of hydraulic stress to the corresponding hydraulic strain will be ______. (Given : Density of water is 1000 kg m⁻³ and g=9.8 m s⁻².)

Asked in JEE Main 17th March 2nd Shift 2021 · Bulk modulus and compressibility

Answer: (1) 1.44×10⁹ N m⁻²

Step-by-step solution

Given: h=2 km=2000 m, ρ=1000 kg m⁻³, g=9.8 m s⁻², (Δ V)/V=1.36%=0.0136.

The stress-to-strain ratio asked for is exactly the bulk modulus, B=(ρ gh)/(Δ V/V).

Hydraulic stress =ρ gh=1000×9.8×2000=1.96×10⁷ N m⁻².

B=(1.96×10⁷)/(0.0136)=1.44×10⁹ N m⁻².

Why the other options are wrong

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