The increase in the pressure required to decrease the volume (Δ V) of water is 6.3×10⁷ N m⁻². The percentage decrease in the volume is . (Bulk modulus of water =2.1×10⁹ N m⁻²)

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(2) 3%. Given: Δ P=6.3×10⁷ N m⁻² and B=2.1×10⁹ N m⁻². B=(Δ P)/(|(Δ V)/V|), so |(Δ V)/V|=(Δ P)/B. |(Δ V)/V|=(6.3×10⁷)/(2.1×10⁹)=3×10⁻². As a percentage this is 3%.

The increase in the pressure required to decrease the volume (Δ V) of water is 6.3×10⁷ N m⁻². The percentage decrease in the volume is ______. (Bulk modulus of water =2.1×10⁹ N m⁻²)

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