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The coercivity of a magnet is 5 × 10³ A/m. The amount of current required to be passed in a solenoid of length 30 cm and the number of turns 150, so that the magnet gets demagnetised when inside the solenoid is ______ A.

Asked in JEE Main 8th April 2nd Shift 2024 · Magnetisation, intensity and susceptibility

Answer: 10

Step-by-step solution

Demagnetising needs H = nI equal to the coercivity.

n = (150)/(0.3) = 500 m⁻¹.

I = (5 × 10³)/(500) = 10 A.

→ 10

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