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The magnetic moment of a bar magnet is 0.5 A m². It is suspended in a uniform magnetic field of 8 × 10⁻² T. The work done in rotating it from its most stable to most unstable position is

Asked in JEE Main 4th April 2nd Shift 2024 · Dipole in a uniform field

Answer: (2) 8 × 10⁻² J

Step-by-step solution

Most stable: θ = 0, U = -MB; most unstable: θ = 180°, U = +MB.

W = 2MB = 2 × 0.5 × 8 × 10⁻² = 8 × 10⁻² J.

Why the other options are wrong

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