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A capillary tube A is dipped in water. Another identical tube B is dipped in a soap-water solution. Each choice below describes a sketch of the two tubes standing side by side in their beakers, with the risen column shown in each. Which of them shows the relative nature of the liquid columns in the two tubes?

Asked in AIEEE 2008 · Capillary rise

Figure: Capillary rise
Answer: (4) The column in A is higher than the column in B.

Step-by-step solution

Given: two identical tubes, A in water and B in soap solution, so r is the same and the densities are practically equal.

For a wetting liquid h=(2T cos θ)/(rρ g), so with everything else fixed h∝ T.

Soap is a surfactant: its molecules collect at the free surface and weaken it, so Tₛₒₐₚ<T_water.

Hence the soap solution climbs less than water does.

The column in A stands higher than the column in B.

Why the other options are wrong

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