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Asked in AIEEE 2008 · Capillary rise
Given: two identical tubes, A in water and B in soap solution, so r is the same and the densities are practically equal.
For a wetting liquid h=(2T cos θ)/(rρ g), so with everything else fixed h∝ T.
Soap is a surfactant: its molecules collect at the free surface and weaken it, so Tₛₒₐₚ<T_water.
Hence the soap solution climbs less than water does.
The column in A stands higher than the column in B.
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