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If the terminal speed of a sphere of gold (density =19.5 kg m⁻³) is 0.2 m s⁻¹ in a viscous liquid (density =1.5 kg m⁻³), find the terminal speed of a sphere of silver (density =10.5 kg m⁻³) of the same size in the same liquid.

Asked in AIEEE 2006 · Terminal velocity and its dependences

Answer: (4) 0.1 m s⁻¹

Step-by-step solution

Given: two spheres of the same radius in the same liquid, so only the density difference changes.

vₜ=(2r²(ρ-σ)g)/(9η), so vₜ∝(ρ-σ).

Gold: 19.5-1.5=18. Silver: 10.5-1.5=9, exactly half.

v₂=0.2×9/(18).

v₂=0.1 m s⁻¹.

Why the other options are wrong

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