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Eight equal drops of water are falling through air with a steady speed of 10 cm s⁻¹. If the drops coalesce, the new steady speed is

Asked in JEE Main 11th April 2nd Shift 2023 · Coalescing and splitting drops

Answer: (2) 40 cm s⁻¹

Step-by-step solution

Given: 8 identical drops, each at a terminal speed of 10 cm s⁻¹, merging into one.

Volume is conserved: 4/3π R³=8×4/3π r³, so R=2r.

Terminal velocity v=(2r²(ρ-σ)g)/(9η)∝ r².

v'=10×(R/r)²=10×4.

v'=40 cm s⁻¹.

Why the other options are wrong

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