Practice portal › Mechanical Properties of Fluids › Viscosity and Stokes' Law
Asked in JEE Main 8th April 1st Shift 2019 · Reynolds number
Given: Q=100 L min⁻¹=(0.1)/(60)=1.67×10⁻³ m³ s⁻¹, r=5×10⁻² m, ρ=10³ kg m⁻³, η=10⁻³ Pa s.
Mean speed: v=Q/(π r²)=(1.67×10⁻³)/(7.85×10⁻³)=0.212 m s⁻¹.
The Reynolds number uses the diameter as the length scale, Rₑ=(ρ vD)/η with D=2r=0.1 m.
Rₑ=(10³×0.212×0.1)/(10⁻³)=2.1×10⁴.
So the Reynolds number is of the order of 10⁴ — well past the turbulent threshold.
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