Practice portal › Mechanical Properties of Fluids › Viscosity and Stokes' Law
Asked in JEE Main 21st Jan 2nd Shift 2026 · Errors and experimental statements
Given: a sphere falling at its terminal speed v₀, so weight, buoyancy and Stokes drag balance.
4/3π r³(σ-ρ)g=6πη rv₀, which gives η=(2r²(σ-ρ)g)/(9v₀).
Only r and v₀ are measured here, and in that expression η∝(r²)/(v₀).
For a product of powers the fractional errors add, each weighted by the magnitude of its exponent.
(Δη)/η=2(Δ r)/r+(Δ v₀)/(v₀).
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