Practice portal › Mechanical Properties of Fluids › Torricelli's Law and Efflux
Asked in JEE Main 9th Jan 2nd Shift 2019 · Efflux speed and range
Given: Q=0.74 m³ min⁻¹=(0.74)/(60)=1.233×10⁻² m³ s⁻¹, opening radius r=2 cm=0.02 m.
Area of the opening: a=π r²=π(4×10⁻⁴)=1.2566×10⁻³ m².
Efflux speed: v=Q/a=(1.233×10⁻²)/(1.2566×10⁻³)=9.81 m s⁻¹.
Torricelli's law for a tank open to the air: v=√2gh, so h=(v²)/(2g)=(96.3)/(19.6).
h=4.9 m, closest to 4.8 m.
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