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The top of a water tank is open to air and its water level is maintained. It is giving out 0.74 m³ of water per minute through a circular opening of 2 cm radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to

Asked in JEE Main 9th Jan 2nd Shift 2019 · Efflux speed and range

Answer: (4) 4.8 m

Step-by-step solution

Given: Q=0.74 m³ min⁻¹=(0.74)/(60)=1.233×10⁻² m³ s⁻¹, opening radius r=2 cm=0.02 m.

Area of the opening: a=π r²=π(4×10⁻⁴)=1.2566×10⁻³ m².

Efflux speed: v=Q/a=(1.233×10⁻²)/(1.2566×10⁻³)=9.81 m s⁻¹.

Torricelli's law for a tank open to the air: v=√2gh, so h=(v²)/(2g)=(96.3)/(19.6).

h=4.9 m, closest to 4.8 m.

Why the other options are wrong

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