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Asked in JEE Main 27th Jan 2nd Shift 2024 · Bernoulli's equation
Given: static reading p₁=4.5×10⁴ and flowing reading p₂=2.0×10⁴ N m⁻², water of density ρ=1000 kg m⁻³.
With the valve shut the water is at rest, so the whole of the fall in the gauge reading is dynamic pressure.
p₁-p₂=1/2ρ v², and p₁-p₂=2.5×10⁴ N m⁻².
v²=(2(2.5×10⁴))/(1000)=50, so v=√50 m s⁻¹.
Comparing with v=√V gives V=50.
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