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A ball is made of a material of density ρ, where ρₒᵢₗ<ρ<ρ_water, with ρₒᵢₗ and ρ_water representing the densities of oil and water respectively. The oil and water are immiscible. If the above ball is in equilibrium in a mixture of this oil and water, which of the following describes its equilibrium position?

Asked in AIEEE 2010 · Two liquids, cavities and relative density

Figure: Two liquids, cavities and relative density
Answer: (3) Oil above water, with the ball resting at the oil--water interface.

Step-by-step solution

Idea: two immiscible liquids settle with the lighter one on top, so the oil layer lies above the water layer.

The ball is denser than the oil, ρ>ρₒᵢₗ, so it cannot float in the oil and sinks through it.

The ball is lighter than water, ρ<ρ_water, so it cannot sink into the water either.

It therefore settles at the boundary, partly in each liquid, with the submerged fractions adjusting until the two upthrusts together carry its weight.

That is the picture described in option 3.

Why the other options are wrong

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