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Asked in JEE Main 15th April 1st Shift 2023 · Conversion to ammeter and voltmeter
Voltmeter: R = (50)/(10⁻³) - 54 = 49946 Ω ≈ 50 kΩ
Ammeter: r = (I_gG)/(I - I_g) = (1 × 54)/9 = 6 Ω
So (A) and (C) are correct.
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