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A galvanometer has a coil of resistance 200 Ω with a full scale deflection at 20 μA. The value of resistance to be added to use it as an ammeter of range (0-20) mA is

Asked in JEE Main 9th April 1st Shift 2024 · Conversion to ammeter and voltmeter

Answer: (4) 0.20 Ω

Step-by-step solution

S = (I_gG)/(I - I_g) = (20 × 10⁻⁶ × 200)/(20 × 10⁻³ - 20 × 10⁻⁶)

S = (4 × 10⁻³)/(0.01998) ≈ 0.20 Ω, in parallel.

Why the other options are wrong

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