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Two long straight wires P and Q carrying equal current 10 A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F₁. If distance between wires is halved and currents on them are doubled, force F₂ on 10 cm length of wire P will be

Asked in JEE Main 24th Jan 1st Shift 2023 · Force between parallel currents

• (1) 10F₁
• (2) 8F₁
• (3) (F₁)/8
• (4) (F₁)/(10)

Step-by-step solution

Why the other options are wrong

• (1) Adds the factors instead of multiplying them.
• (3) Inverts the ratio, taking force proportional to d/I².
• (4) Adds the factors and inverts the ratio.

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