Practice portal › Moving Charges and Magnetism › Ampere's Circuital Law, Solenoid and Toroid
Asked in JEE Main 2006 · Solenoid, toroid and field energy
B=μ₀ n i, so (B₂)/(B₁)=(n₂ i₂)/(n₁ i₁)=(100)/(200)×1/3=1/6.
B₂=(6.28×10⁻²)/6=1.05×10⁻² Wb/m²
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