Two circular coils P and Q of 100 turns each have same radius of π cm. The currents in P and Q are 1 A and 2 A respectively. P and Q are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is √x mT, where x=…

Question

Two circular coils P and Q of 100 turns each have same radius of π cm. The currents in P and Q are 1 A and 2 A respectively. P and Q are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is √x mT, where x= . [Use μ₀=4π×10⁻⁷ T m A⁻¹]

Accepted Answer

20. B=(Nμ₀ I)/(2R) with (Nμ₀)/(2R)=(100×4π×10⁻⁷)/(2×0.01π)=2×10⁻³ T/A. B_P=2 mT, B_Q=4 mT, perpendicular. B=√4+16=√20 mT → 20

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