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Asked in JEE Main 8th April 2nd Shift 2023 · Centre and axis of a loop
With axial distance d: (B_centre)/(Bₐₓᵢₛ)=((r²+d²)^3/2)/(r³).
Put d=r: ratio =((2r²)^3/2)/(r³)=2√2=√8
→ 8
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