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The ratio of magnetic field at the centre of a current carrying coil of radius r to the magnetic field at distance r from the centre of coil on its axis is √x:1. The value of x is ______.

Asked in JEE Main 8th April 2nd Shift 2023 · Centre and axis of a loop

Answer: 8

Step-by-step solution

With axial distance d: (B_centre)/(Bₐₓᵢₛ)=((r²+d²)^3/2)/(r³).

Put d=r: ratio =((2r²)^3/2)/(r³)=2√2=√8

→ 8

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