Practice portal › Moving Charges and Magnetism › Biot-Savart Law: Straight Wires and Arcs
Asked in JEE Main 8th April 2nd Shift 2019 · Straight wire segments
P is at distance d from each wire, so each wire gives (μ₀ I)/(2π d) along ±ẑ.
Upward current in the vertical wire gives -ẑ at P (P is to its right).
Current along +x̂ in the horizontal wire gives +ẑ at P (P is above it).
Equal and opposite, so Bₙₑₜ=0
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer