Practice portal › Moving Charges and Magnetism › Biot-Savart Law: Straight Wires and Arcs
Asked in JEE Main 2016 · Arcs and combined shapes
Circle: R=l/(2π), B_A=(μ₀ I)/(2R)=(πμ₀ I)/l.
Square: a=l/4, B_B=4×(μ₀ I)/(4π(a/2))(2 sin 45°)=(2√2μ₀ I)/(π a)=(8√2μ₀ I)/(π l).
(B_A)/(B_B)=(π²)/(8√2)
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