A charged particle of 2 μC accelerated by a potential of 100 V enters a region of uniform magnetic field of magnitude 4 mT at right angle to the direction of the field. The charged particle completes a semicircle of radius 3 cm inside the magnetic field. The mass of the charge is ×10⁻¹⁸ kg.

Question

Accepted Answer

144. r=(√2mqV)/(qB)⇒ m=(qr²B²)/(2V) m=((2×10⁻⁶)(9×10⁻⁴)(16×10⁻⁶))/(2×100) m=1.44×10⁻¹⁶ kg=144×10⁻¹⁸ kg → 144

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