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A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B. The time taken by the particle to complete one revolution is

Asked in JEE Main 2005 · Circular motion: radius, period and energy

Answer: (2) (2π m)/(qB)

Step-by-step solution

r = (mv)/(qB).

T = (2π r)/v = (2π m)/(qB).

Why the other options are wrong

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